I was reading C++ Primer from Stanley B. Lippman and at the part of flow control it shows an example of a for-loop like this one:
#include <iostream>
int main(void){
int sum=0;
for (int val=1; val <= 10; val++)
sum +=val;
std::cout << sum << std::endl;
return 0;
}
If I try std::cout << val; outside of the for-loop, the IDE gives me an erro. But I want to understand why it happens and how it is different from this code:
#include <iostream>
int main(void){
int sum=0;
int val;
for ( val=1; val <= 10; val++)
sum +=val;
std::cout << sum << std::endl;
std::cout << val;
return 0;
}
Where I can actually print the val value without any problem.
Does it have something to do with local variable considering the for-loop a function that we are using inside of the main?
via Chebli Mohamed
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